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If a compound on analysis was found to c...

If a compound on analysis was found to contain `C=18.5%, h=1.55%,Cl=55.04%` and `O=25.81%`, then its empirical formul is

A

`CHClO`

B

`CH_(2)ClO`

C

`C_(2)H_(2)OCl`

D

`ClCH_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
A
`"Element No. of moles Simple ratio"`
`C=18.5%" "18.5//12=1.55" "1`
`H=1.55%" "1.55//1=1.55" "1`
`Cl=55.04%" "55.04//35.5=1.55" "1`
`O=24.81%" "24.81//16=1.55" "1`
Hence , formula `=CHClO`.
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