A hydrocarbon contains 10.5 gm carbon an...

A hydrocarbon contains `10.5 gm` carbon and `1 gm` hydrogen. Its `2.4 gm` has `1 L` volume at `1 atm` and `127^(@)C`, hydrocarbon is

`C_(6)H_(7)`

`C_(6)H_(8)`

`C_(5)H_(6)`

None of these

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The correct Answer is:

`C=10.5g=(10.5)/(12)mol=0.87mol`
`H=1g=(1)/(1)=1mol`
`:. (C_(0.87)H_(1))_(7)=C_(6.09)H_(7)=C_(6)H_(7)`
`PV=nRT,PV=(w)/(m)RT`
`1xx1=(2.4)/(m)xx0.082xx400`
`m=2.4xx0.082xx400=78.42=79`

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