If the distance of a given point `(alpha,beta)` from each of two straight lines `y = mx` through the origin is d, then `(alpha gamma- beta x)^(2)` is equal to

The distance of a point (alpha, beta) from the origin is ....

The distance of a point (alpha, beta) from the origin is ....

Distance of the point (alpha, beta,gamma) from y-axis is

The distance of the point P ( alpha, beta , gamma) from x-axis is

The distance of the point P ( alpha , beta , gamma) from y-axis is

Distance of the point (alpha, beta, gamma) from the y-axis is

The distance from a point (alpha,beta) to a pair of lines passing through the origin is d. Then the equation to the pair of lines is

Distance of the point (alpha,beta,gamma) from Y- axis is …........

Consider a circle (x-alpha)^(2)+(y-beta)^(2)=50 ,where alpha,beta>0 .If the circle touches the line y+x=0 at the point "P" ,whose distance from the origin is 4sqrt(2) ,then (alpha+beta)^(2) is equal to

If the distances of the vertices of a triangle =ABC from the points of contacts of the incercle with sides are alpha,beta and gamma then prove that r^(2)=(alpha beta gamma)/(alpha=beta+gamma)