[" 1.If "alpha,beta" are the roots of "x^(2)+px-q=0" and "gamma],[[delta" are the roots of "x^(2)+px+r=0(q+r!=0)],[" then "((alpha-gamma))/((beta-gamma))((alpha-delta))/((beta-delta))=],[(1)1]]

If alpha , beta are the roots of x^2 +px -q=0 and gamma , delta are the roots of x^2 +px+r=0 then (alpha - gamma ) ( beta - gamma) ( alpha - delta ) ( beta- delta )=

If alpha,beta are the roots of x^(2)+px+q=0and gamma,delta are the roots of x^(2)+px+r=0, then ((alpha-gamma)(alpha-delta))/((beta-gamma)(beta-delta))= a.1b.q c.r d.q+r

If alpha , beta are the roots of x^2 + px +1=0 and gamma , delta are the roots of x^2 +qx +1=0 then (alpha - gamma )(beta - gamma)(alpha + delta )( beta + delta )=

If alpha,beta are the roots of x^(2)+ax-b=0 and gamma,delta are the roots of x^(2)+ax+b=0 then (alpha-gamma)(alpha-delta)(beta-gamma)(beta-delta)=

If alpha,beta be the roots x^2+px-q=0 and gamma,delta be the roots of x^2+px+r=0, p+rphi0 ,then ((alpha-gamma)(alpha-delta))/((beta-gamma)(beta-delta)) is equal to

if alpha,beta are the roots of quadratic equation x^(2)+px+q=0 then gamma,delta are the roots of x^(2)+px-r=0, then (alpha-gamma)(alpha-delta)

If alpha,beta are roots of x^(2)+-px+1=0 and gamma,delta are the roots of x^(2)+qx+1=0 ,then prove that q^(2)-p^(2)=(alpha-gamma)(beta-gamma)(alpha+delta)(beta+delta)

If alpha and beta are the roots of x^(2) +px+q=0 and gamma , delta are the roots of x^(2) +rx+x=0 , then evaluate (alpha - gamma ) ( beta - gamma ) (alpha - delta ) ( beta - delta) in terms of p,q,r and s .

If alpha and beta are the roots of x^(2) +px+q=0 and gamma, delta are the roots of x^(2)+rx+s=0, then evaluate (alpha-gamma)(beta-gamma) (alpha-delta) (beta-deta) in terma of p,q, r and s.

If alpha,beta are the roots of x^2+p x+q=0a n dgamma,delta are the roots of x^2+p x+r=0, then ((alpha-gamma)(alpha-delta))/((beta-gamma)(beta-delta))= a. 1 b. q c. r d. q+r