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[" 1."2+2.2^(2)+3.2^(2)+............n.2^...

[" 1."2+2.2^(2)+3.2^(2)+............n.2^(n)=(n-1)2^(n+1)+2],[" anforder "3" ivoldel Rresion "]

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1*2+2*2^(2)+3*2^(3)+..........+n*2^(n)=(n-1)2^(n+1)+2

1.2+2.2^(2)+3.2^(3)+....+n.2^(n)=(n-1)2^(n-1)+2

1.2+2.2^(2)+3.2^(3)+....+n.2^(n)=(n-1)2^(n-1)+2

1.2+2.2^(2)+3.2^(3)dots...n.2^(n)=(n-1)2^(n+1)+2

1^(2)+2^(2)+3^(2)+..........+n^(2)=(n(n+1)(2n+1))/(6)

1^(2)+2^(2)+3^(2)+............+n^(2)=(n(n+1)(2n+1))/6 forall n in N.

1*2+2*2^(2)+3*2^(3)+*2^(n)=(n-1)2^(n+1)+2

Prove that 1^(2)+2^(2)+3^(2)+.....+n^(2)=(n(n+1)(2n+1))/6

1 ^(2) + 2^(2) + 3^(2) + . . . + n^(2) = (n (n + 1) (2 n + 1))/( 6)