Find the specific heat capacities `c_v` and `c_p` for a gaseous mixture consisting of `7.0 g` of nitrogen and `20 g` of argon. The gases are assumed to be ideal.

Explanation

From the previous problem
`C_V = (v_1 (R)/(gamma_1 - 1)+v_2(R)/(gamma_2 - 1))/(v_1 + v_2) = 15.2 J//"mole". K`
and `C_p = (v_1 (gamma_1 R)/(gamma_1 - 1)+v_2(gamma_2 R)/(gamma_2 - 1))/(v_1 + v_2) = 23.85 J//"mole". K`
Now molar mass of the mixture `(M) = ("Total mass")/("Total number of moles") = (20 + 7)/((1)/(2)+(1)/(4)) = 36`
Hence `C_V = (C_V)/(M) = 0.42 J//g.K` and `C_p = (C_p)/(M) = 0.66 J//g.K`.