How many degress of freedom have the gas molecules, if under standard conditions the gas density is `rho = 1.3 kg//m^3` and velocity of sound propagation o it is `v = 330m//s` ?

Explanation

From the formula
`v = sqrt((gamma p)/(rho)), gamma = (pV^2)/(p)`
If `i`= number if degrees of freedom of the gas then
`C_p = C_V + RT` and `C_V = (i)/(2) RT`
`gamma = (C_p)/(C_v) = 1 + (2)/(i)` or `i = (2)/(gamma - 1) =(2)/((pv^2)/(p) -1)`.