Calculate the most probable, the mean, and the root mean square velocities of a molecule of a gas whose density under standard atmospheric pressure is equal to `rho = 1.00 g//1`.

Explanation

`v_p = sqrt((2 kT)/(m)) = sqrt((2 RT)/(M)) = sqrt((2 p)/(rho)) = 0.45 km//s`,
`v_(av) = sqrt((8)/(pi) (p)/(rho)) = .51 km//s` and `v_(rms) = sqrt((3 p)/(rho)) = 0.55 km//s`.