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When examining the suspended gamboge dro...

When examining the suspended gamboge droplets under a microscope, their average numbers in the layers separated by the distance `h = 40 mu m`, and their density exceeds that of the surrounding fluid by `Delta rho = 0.20 g//cm^3`. Find Avogadro's number from these data.

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Here `F = (pi)/(6) d^3 Delta rho g = (RT 1n eta)/(N_a h)` or `N_a = (6 RT 1n eta)/(pi d^3 g Delta rho h)`
In the problem, `(eta)/(eta_0) = 1.39` here
`T = 290 K, eta = 2, h = 4 xx 10^-5 m, d = 4 xx 10^-7 m, g = 9.8 m//s^2, Delta rho = 0.2 xx 10^3 kg//m^2`
and `R = 8.31 J//K`
Hence, `N_a = (6 xx 8.31 xx 290 xx 1 n 2)/(pi xx 64 xx 9.8 200 xx 4) xx 10^26= 6.36 xx 10^23 "mole"^-1`.
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