Find the efficiency of a cycle consisting of two isobaric and two adiabatic lines, if the pressure changes `n` times within the cycle. The working substance is an ideal gas whose adiabatic exponent is equal to `gamma`.

Explanation

`Q_1 = (C_p)/(R) p_1 (V _2 - V_1), Q'_2 = (C_p)/(R) p_2 (V_3 - V_4)` ltbRgt So `eta = 1 -(p_2(V_3 - V_4))/(p_1 (V_2 - V_1))`
Now `p_1 = n p_2, p_1 V_2^gamma` or `V_3 = n (1)/(gamma) V_2`
`p_2 V_4^gamma = p_1 V_1^gamma` or `V_4 = n^((1)/(gamma)) V_1`
so `eta = 1 - (1)/(n). n^((1)/(gamma)) = 1 - n^((1)/(gamma)-1)`
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