The condition are the same as in the foregoing problem with the exception that the isothermal process proceeds at the maximum temperature of the whole cycle.

Explanation

Here the isothermal process proceeds at the maximum temperature instead of at the minimum temperature of the cycle as in `2.120`.
(a) Here `p_1 V_1 = p_2 V_0, p_2 = (p_1)/(n)`
`p_2 V_1^gamma = p_0 V_0^gamma` or `p_1 V_1^gamma =np_0 V_0^gamma`
i.e., `V_1^(gamma - 1) = n V_0^(gamma -1)` or `V_1 = V_0 n^((1)/(gamma -1))`
`Q'_2 = C_V T_0(1 -(1)/(n)), Q_1 = RT_0 1n (V_1)/(V_0) = (RT_0)/(gamma - 1) 1n n = C
_V T_0 1n n`
Thus `eta = 1-(Q'_2)/(Q_1) = 1- (n -1)/(n 1n n)`
(b) Here `V_2 = (V_1)/(n), p_0 V_0 = p_1 V_1`
`p_0 V_0^gamma = p_1 V_2^gamma = p_1 n^(- gamma) V_1 ^gamma = V_0^(gamma - 1) n^(- gamma) V_1^(gamma -1)`or `V_1 = n^((gamma//gamma - 1)) V_0`
`Q'_2 = C_p T_0(1 - (1)/(n)), Q_1 = RT_0 1n (V_1)/(V_0) = (R gamma)/(gamma - 1) T_0 1n n = C_p T_0 1n n`
Thus `eta = 1 - (n -1)/(n 1n n)`.