Find the entropy increment of an aluminium bar of mass `m = 3.0 kg` on its heating from the temperature `T_1 = 300 K` up to `T_2 = 600 K` if in this temperature interval the specific heat capacity of aluminimum varies as `c = a + bT`, where `a = 0.77 J//(g.K), b = 0.46 mJ//(g. k^2)`.

Explanation

`Delta S = int_(T_1)^(T_2) (CdT)/(T) = int_(T_1)^(T_2) (m(a + bT))/(T) dT = mb (T_2 - T_1) + ma 1n (T_2)/(T_1)`.