Find the specific volume of benzence `(C_6 H_6)` in critical state if its critical temperature `T_(cr) = 562 K` and critical pressure `p_(cr) = 47 atm`.

Explanation

Specific volume is molar volume divided by molecular weight. Thus
`V'_(Cr) = (V_(M_(Cr)))/(M) = (3 RT_(Cr))/(8 Mp_(Cr)) = (3 xx 0.82 xx 562)/(8 xx 78 xx 47)(litre)/(g) = 4.71 (c c)/(g)`.