Find the increment of the ice melting temperature in the vicinity of `0 ^@C` when the pressure is increased by `Delta p = 1.00 atm`. The specific volume of ice exceeds that of water by `Delta V' = 0.091 cm^3//g`.

Explanation

From the Claissius-Clapeyron `(C-C)` equations
`(dT)/(dp) = (T(V'_2 - V'_1))/(q_12)`
`q_12` is the specific latent heat absorbed in `1 rarr 2 (1 = solid, 2 = liquid)`
`Delta T = (T(V'_w - V'_(ice)))/(q_12) Delta p = - (273 xx .091)/(333) xx 1 (atm xx cm^3 xx K)/("joule")`
`1 (atm xx cm^3)/("Joule")~~ (10^5 (N)/(m^2) xx 10^-6 m^3)/("Joule") = 10^-1, Delta T = -.0075 K`.