An ice which was initially under standard conditions was compressedup to the pressure `p = 640 atm`. Assuming the lowering of the ice melting temperature to be a linear function of pressure under the given conditions, find what fraction of the ice melted. The specific volume of water is less than of ice by `Delta V' = 0.09 cm^3//g`.

Explanation

As before `(2.206)` the lowering of melting point is given by
`Delta T = - (T Delta V')/(q) p`
The superheated ice will then melt in part. The fraction that will melt is
`eta = (CT Delta V')/(q^2) p ~~ .03`.