What would be the interaction force between two coppersphers, each of mass `1 g`, separated by the distance `1m`, if the total electrons charge in them differted from the total charge of the nuclei by one of part cent?

Explanation

Total number of atons in the sphere fo mass `1 gm = (1)/(63.54) xx10^(23)`
So the total auclear charge `lambda = (6.023xx10^(23))/(63.54) xx1.6xx10^(-19)xx29`
Now the charge on the sphere = Total nuclear charge - Total electronic change
`= (6.023xx10^(23))/(63.54)xx1.6xx10^(-19)xx (29xx1)/(100) = 4.298xx10^(2) C`
Hence force of interaction between these two spheres,
`F =(1)/(4pi epsilon_(0)) . ([4.398xx10^(2)]^(2))/(1^(2)) N = 9xx10^(9)xx10^(4) xx19.348 N = 1.74xx10^(15) N`