Demonstrate that at a dielectric-conductor interface the surface density of the dielectric's bound charge `sigma' = -sigma (epsilon - 1)//epsilon`' where `epsilon` is the permittivity, `sigma` is the density of the charge on the conductor.

Explanation

`D_("diel") = epsilon epsilon_(0) E_("diel") = D_("conductor") = sigma`, or `E_("diel") = (sigma)/(epsilon epsilon_(0))`
`P_(n) = (epsilon - 1) epsilon_(0) E_("diel") = (epsilon - 1)/(epsilon) sigma`
`sigma' = P_(n) = (epsilon - 1)/(epsilon) sigma`
This is the surface density of bound charges.