Find the capacitance of a system of identical capacitors between points `A` and `B` are shown in
(a) Fig. `A` (b) Fig `B`

Explanation

(a) Since `varphi_(2) = varphi_(B)` and `varphi_(2) = varphi_(A)`
The arrangement of capacitos shown in the problem is equivalent to the arrangment shown in Fig.

and hence the capacitors between `A` and `B` is ,
(B) From the symeetry of the problem, there is no `P.d.` between `D` and `E`. So, the combination reduces to a simple arrangement redueces to a simple arrangement shown in FIg, and hence teh net capacitanace,
`C_(0) = (C)/(2) + (C)/(2) = C`