Fig, shows a toridal solenoidi whose cross-section is rectangular. Find the magnetic flux thorugh the winding equlals `I = 1.7 A`, the total number of turns Is `N = 1000`, the ratio of the outside diameter to the inside one is `eta = 1.6`, and the height is equal to `h = 5.0 cm`.

Explanation

`B_(varphi)2pir=mu_(0)NI`
or, `B_(varphi)=(mu_(0)NI)/(2pir)`
Then, `Phi=int_(a)^(b)B_(varphi)hdr,alerleb=(mu_(0))/(4pi)2Nln eta` where `eta=b//a`