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[" 16."sin36^(@)sin72^(@)sin108^(@)sin14...

[" 16."sin36^(@)sin72^(@)sin108^(@)sin144^(@)(1)/(4 pi)=(121+)/(417)" and "],[[" (a) "1/4," (b) "1/16],[" (c) "3/4," fet "5/16]]

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sin36^(@)sin72^(@)sin108^(@)sin144^(@)=(5)/(16)

sin 36^(º)sin 72^(º) sin108^(º) sin 144^(º) =

sin 36^(º)sin 72^(º) sin108^(º) sin 144^(º) =

Prove that: sin36^(@)s in72^(0)s in108^(0)s in144^(0)=(5)/(16)

sin36^@ sin72^@ sin108^@ sin144^@ is equal to:

sin 180^(@) sin 70^(@) + sin 16^(@) sin 36^(@)=

sin18^@sin70^@+sin16^@sin36^@=