Home
Class 12
PHYSICS
A plane loop is shaped as two squares (F...

A plane loop is shaped as two squares (Fig) and placed in a uniform magnetic field at right angle to the loop's plane. The magnetic induction varies with time as `B =B_(0) sin (omega)t, where B_(0) = 10 mT and (omega) = 100 rads^(-1)`. The wires do not touch at point A. If resistance per unit length of the loop is `50 m(Omega)// m`, then amplitude of current induced in the loop is

Text Solution

Verified by Experts

The loops are connected in such a way that if the current is clockwise in one, it is anticlockwise in the other. Hence the e.m.f in loop `b` opposes the e.m.f in loop `a`.
`e.m.f` in loop `a = (d)/(dt) (a^(2) B) = a^(2) (d)/(dt) (B_(0) sin omega t)`
Similarly, `e.m.f` in loop `b = b^(2) B_(0) omega cos omega t`.
Hence, net `e.m.f` in the circuit `= (a^(2) - b^(2)) B_(0) omega cos omega t`, as both the e.m.f's are in opposite sense, and resistance of the circuit `= 4(a + b) rho`
Therefore, the amplitude of the current
`= ((a^(2) - b^(2))B_(0) omega)/(4 (a + b) rho) = 0.5 A`.
Promotional Banner

Topper's Solved these Questions

  • ELECTRODYNAMICS

    IE IRODOV, LA SENA & SS KROTOV|Exercise Motion Of Charged Particle In Magnetic Field|36 Videos
  • ELECTRODYNAMICS

    IE IRODOV, LA SENA & SS KROTOV|Exercise Constant Magnetic Fiels - Magnetics|69 Videos
  • ELECTRICITY AND MAGNETISM

    IE IRODOV, LA SENA & SS KROTOV|Exercise All Questions|6 Videos
  • ELECTROMAGNETISM

    IE IRODOV, LA SENA & SS KROTOV|Exercise All Questions|24 Videos
IE IRODOV, LA SENA & SS KROTOV-ELECTRODYNAMICS-Electromagnetic Induction
  1. A connector AB can slide without frictiion along a II-shaped cond...

    Text Solution

    |

  2. Fig. illustrates plane figures made of thin conductors which are lo...

    Text Solution

    |

  3. A plane loop is shaped as two squares (Fig) and placed in a uniform ma...

    Text Solution

    |

  4. A plane loop is shaped as two squares (Fig) and placed in a uniform ma...

    Text Solution

    |

  5. A pi shaped metal frame is located in a uniform magnetic field perpend...

    Text Solution

    |

  6. In a long staright solenoid with cross-sectional radius a and nu...

    Text Solution

    |

  7. A long straight solenoid of cross-sectional diameter d = 5 cm and wi...

    Text Solution

    |

  8. A long solenoid of cross-sectional radius a has a thin insulates ...

    Text Solution

    |

  9. A thin non-conducting ring of mass m carrying a charge q can fre...

    Text Solution

    |

  10. A thin wire ring of radius a and resitance r is located inside a lon...

    Text Solution

    |

  11. A magentic flux through a statinary loop with a resistance R varies...

    Text Solution

    |

  12. In the middle of a long solenoid there is a coaxial ring of square...

    Text Solution

    |

  13. How many meters of a thin wire are required to manufacture a soleno...

    Text Solution

    |

  14. Find the inductance of a solenoid of length l whose winding is ma...

    Text Solution

    |

  15. A coil of inductance L = 300 mH and resitance R = 140 m Omega is co...

    Text Solution

    |

  16. Calculate the time constant tau of a straight solenoid of length ...

    Text Solution

    |

  17. Find the inductance of a unit length of a cable consisting of two...

    Text Solution

    |

  18. Calculate the inducatance of a doughunt solenoid whose inside radius...

    Text Solution

    |

  19. Calculate the inuctance of a unit length of a double tape line (Fig)...

    Text Solution

    |

  20. Find the inductane of a unit length of a double line if the radius ...

    Text Solution

    |