A small body of mass `m` is fixed to the middle of a stretched string of length `2l`. In the equlibrium position the string tension is equal to `T_(0)`. Find the angular freqency of small oscillations of the body in the transverse direction. The mass of the string is negligible, the gravitational field is absent.

Explanation

To find the angular frequency of small oscillations of a mass \( m \) fixed to the middle of a stretched string of length \( 2l \) with tension \( T_0 \), we can follow these steps:

### Step 1: Understand the system
The mass \( m \) is suspended at the midpoint of a string of length \( 2l \). Since the gravitational field is absent, the only forces acting on the mass are due to the tension in the string.

### Step 2: Draw the free body diagram
When the mass is displaced slightly from its equilibrium position, the string will form an angle \( \theta \) with the vertical. The tension \( T_0 \) acts along the string, and we can resolve this tension into two components:
- A vertical component \( T_0 \cos \theta \)
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