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An electromagnetic wave of frequency v=3...

An electromagnetic wave of frequency `v=3.0 MHz` passes from vacuum into a dielectric medium with permittivity `epsilon=4.0`. Then

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The velocity of light in a medium of relative permittivity `epsilon` is `(c)/(sqrt(epsilon))`. Thus the change in wavelength of light `(` from its value in vacuum to its value in the medium `)` is
`Delta lambda=(c//sqrt(epsilon))/(v)-(c)/( v)=(c)/(v)((1)/sqrt(epsilon)-1)=-50M`.
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Knowledge Check

  • An electromagnetic wave of v=3 MHz passes from vacuum into dielectric medium with epsi= 4 epsi_0 . then

    A
    Wavelength is doubled and frequency becomes half .
    B
    Wavelength is doubled and frequency is same .
    C
    Wavelength and frequency both remain unchanged .
    D
    Wavelength is halved but frequency remains same .

  • The electromagnetic wave of frequency 3 MHz to 30 MHz are

    A
    in ground wave propagation
    B
    in sky wave propagation
    C
    in microwave propagation
    D
    in satellite communication

  • The electromagnetic wave of frequency 2 MHz to 30 MHz are

    A
    In ground wave propagation
    B
    In sky wave propagation
    C
    In microwave propagation
    D
    Both `(a)` and `(b)`

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