Calculate the de Broglie wavelength of an electron, proton and uranium atom, all having the same kinetic energy `100eV`.

Explanation

The kinetic energy is nonerelatativistic in all three cases. Now
`lambda=(2pi ħ)/(P)=(2pi ħ)/(sqrt(2mT))`
Using `T=1.602xx10^(-17)` Joules, we get
`lambda_(e)= 122.6p m`
`lambda_(p)= 2.86p m`
`lambda_(U)=(lambda_(p))/(sqrt(238))=0.185p m`
(where we have used a mass number of `238` for the `U` nucleus).