Show that for the particle whose coordinate incertainty is `Deltax=lambda//2pi`, where `lambda` is its de Broglie wavelength, the velocity uncertainty is of the same order of magnitude as the particle's velocity itself.

Explanation

If `Deltax=lambda//2pi=(2piħ)/(P).(1)/(2pi)=(ħ)/(P)=(ħ)/(mv)`
Thus `Deltavunderset(~)gt(ħ)/(mDeltax)=v`
Thus `Deltav` is of the same order as `v`.