Find the enrgy required of seperation of a `Ne^(20)` nucleus into two alpha-particles and a `C^(12)` nucleus if it is known that binding energies per one nucleon in `Ne^(20), He^(4)` and `C^(12)` nuclei are equal to `8.03, 7.07`, and `7.68MeV` respectively.

Explanation

Required energy is simply the differecne in total binding energies-
`=B.E o f Ne^(20)-2(B.E of He^(4))-B.E o f C^(12)`
`=20 epsilon_(Ne)-8 epsilon_(alpha)-12 epsilon_(C )`
( `epsilon` is binding energy per unit nucleon).
Substitution gives `11.88MeV`