" 9."f(x)=sqrt(3x-5)

Find the domain f(x) = sqrt(3x - 5) .

Find the domain f(x) = sqrt(3x - 5) .

The domain of the function f defined by f(x)= sqrt(x^(2)-9) is

Using componendo and dividendo, find the value of x if (sqrt(3x+4)+sqrt(3x-5))/(sqrt(3x+4)-sqrt(3x-5))=9 .

Let f(x) =sqrt(9-x^(2))." then , domain " (f ) =?

If f(9)=9,f'(9)=4,then(lim)_(x rarr9)(sqrt(f(x))-3)/(sqrt(x)-3)=

If f(9)=9 , f'(9)= 4 then lim _ (x rarr9) (sqrt f(x) -3)/(sqrt(x)-3) =_____.

If f(9)=9 and f'(9)=4 then lim_(x to 9)(sqrt(f(x))-3)/(sqrt(x)-3) is equal to -

If f(9)=9" and f'"(9)=4 then Lt_(x to 9)(sqrt(f(x))-3)/(sqrt(x)-3) is equal to

If f be a function such that f(9)=9 and f'(9)=3 , then lim_(xto9)(sqrt(f(x))-3)/(sqrt(x)-3) is equal to