[" 4.Fiet facher "],[[" (i) "9sec^(2)A-9tan^(2)A," aft "3 pi'+499],[" (A) "1," (B) "9]]

9 sec^(2) A - 9 tan^(2) A =

Find the value of 9sec^(2)A-9tan^(2)A

9sec^2A-9tan^2 A is equal to

9sec^(2)A-9tan^(2)A is equal to (a)1(b)9(c)8 (d) 0

9sec^2A-9tan^2A is equal to (a) 1 (b) 9 (c) 8 (d) 0

9 sec ^ 2 A - 9 tan ^ 2 A = ?

Choose the correct option. Justify your choice. (i) 9sec^2A-9tan^2A= (a) 1 (b) 9 (c) 8 (d) 0

Choose the correct option. Justify your choice. (i) 9sec^2A-9tan^2A= (a) 1 (b) 9 (c) 8 (d) 0

[" If "I=(2)/(pi)int_((-pi)/(4))^((pi)/(4))(dx)/((1+e^(sin x)))" then "9I^(2)=--],[[" (A) "(9)/(4),],[" (B) "9],[" (C) "(pi^(2))/(4)],[" (D) "(9 pi^(2))/(4)]]

Choose the correct option.Justify your choice (i) 9sec^(2)A-9tan^(2)A