[" (v) "2x-y=9],[5x+2y=27]

5x-y=9; 6x-2y=10

8x+5y=9 3x+2y=4

2x+3y=5 6x+9y=10

2x-y-5=0; x+3y-9=0

Solve for x & y and find the value of 9x+3y : 2x+5y=13 7x-y=27

Two sides of a triangle are 2x -y =0 and x + y = 3. If its centroid is (2, 3) its third side is (A) x + 5y – 9 = 0 (B) 5x – Y – 9 = 0 (C) x + 5y + 9 = 0 D) 5x – y + 9 = 0

1 + 5x + 3y = 9 2x 3y = 12 X = (x, y) - 4

Equation of the circle cutting orthogonal these circles x^(2)+y^(2)-2x-3y-7=0x^(2)+y^(2)+5x-5y+9=0 and x^(2)+y^(2)+7x-9y+29=0 is: