Home
Class 12
MATHS
The length of perpendicular from the ori...

The length of perpendicular from the origin to the line `vecr=(4hati=2hatj+4hatk)+lamda(3hati+4hatj-5hatk)` is (A) 2 (B) `2sqrt(3)` (C) `6 (D) 7

Promotional Banner

Similar Questions

Explore conceptually related problems

The position vector of the foot of the perpendicular draw from the point 2hati-hatj+5hatk to the line vecr=(11hati-2hatj-8hatk)+lamda(10hati-4hatj-11hatk) is

The position vector of the foot of the perpendicular draw from the point 2hati-hatj+5hatk to the line vecr=(11hati-2hatj-8hatk)+lamda(10hati-4hatj-11hatk) is

The vector equation of the plane containing he line vecr=(-2hati-3hatj+4hatk)+lamda(3hati-2hatj-hatk) and the point hati+2hatj+3hatk is

The vector equation of the plane containing he line vecr=(-2hati-3hatj+4hatk)+lamda(3hati-2hatj-hatk) and the point hati+2hatj+3hatk is

Find the angle between the line vecr=(hati+2hatj-hatk)+lamda(hati-hatj+hatk) and the plane vecr.(2hati-hatj+hatk)=4

The line through hati+3hatj+2hatk and perpendicular to the lines vecr=(hati+2hatj-hatk)+lamda(2hati+hatj+hatk) and vecr=(2hati+6hatj+hatk)+mu(hati+2hatj+3hatk) is

The line through hati+3hatj+2hatk and perpendicular to the lines vecr=(hati+2hatj-hatk)+lamda(2hati+hatj+hatk) and vecr=(2hati+6hatj+hatk)+mu(hati+2hatj+3hatk) is

The line through hati+3hatj+2hatk and perpendicular to the lines vecr=(hati+2hatj-hatk)+lamda(2hati+hatj+hatk) and vecr=(2hati+6hatj+hatk)+mu(hati+2hatj+3hatk) is

The line through hati+3hatj+2hatk and perpendicular to the lines vecr=(hati+2hatj-hatk)+lamda(2hati+hatj+hatk) and vecr=(2hati+6hatj+hatk)+mu(hati+2hatj+3hatk) is

Find the equation of the line perpendicular to the lines : vecr=(3hati+2hatj-4hatk)+lambda(hati+2hatj-2hatk) and vecr=(5hatj-2hatk)+mu(3hati+2hatj+6hatk) and passing through the point (1,1,1)