A body has a time period `T_(1)` under the action of one force and `T_(2)` under the action of another force, the square of the time period when both the forces are acting in the same direction is

A body has a time period (4/5) s under the action of one force and (3/5) s under the action of another force. Then time period when both the forces are acting in the same direction simultaneously will be

A body has a time period (4/5) s under the action of one force and (3/5) s under the action of another force. Then time period when both the forces are acting in the opposite direction simultaneously will be

A particle has a time period of 1s under the action of a certain force and 2 s under the action of another force. Find the time period when the forces are acting in the same direction simultaneously.

A body has a time of 3 s under the action of one force and 4 s under the action of another force. Calculate the time period when both the forces act in the same direction simultaneously. Assume that the body undergoes the same displacement, under the action of the two different forces.

A body executes SHM under the influence of one force with a time period of 0.8second. It has a time period of 0.6 second udner the action of another force. Calculate the time period when both the force act in the same direction simultaneously.

What is net force on a body under the action of a couple ?

A body executing S.H.M. has a period of 3 s under one force and 4 s under another force. Then time period under the action of both the forces together in the same direction is

A body is executing simple harmonic motion under the action of a force F_(1) with time period 1 s. The time period is 2s when body is acted by another force F_(3) . What will be the total time period when both the forces are acting in same direction simultaneously ?