A particle velocity changes from `(2 hati - 3hatj) ms^(-1)` to `(3hati - 2hatj) ms^(-1)` in 2s. If its mass is 1kg, the acceleraton `(ms^(-2))` is

A particle's velocity changes from (2hat I +3 hatj) ms^(-1) in to (3 hati - 2hatj) ms^(-1) in 2s. Its average acceleration in ms^(-2) is

A particle's velocity changes from (2hat I +3 hatj) ms^(-1) in to (3 hati - 2hatj) ms^(-1) in 2s. Its average acceleration in ms^(-2) is

A particle velocity changes from (2hat(i)+3hat(j))ms^(-1) to (2hat(i)-3hat(j))ms^(-1) in 2 s. The acceleration in ms^(-2) is

A particle velocity changes from (2hat(i)+3hat(j))ms^(-1) to (2hat(i)-3hat(j))ms^(-1) in 2 s. The acceleration in ms^(-2) is

The velocity of a 2 kg body is changed from (4hati +3hatj) ms^(-1) to 6hat ms^(-1) . The work done on the body is

A force applied on a particle of mass 2 kg changes its velocity from (hati + 2 hatj ) ms^(-1) "to" (4hati +6hatj )ms^(-1) ​. The work done by the force in this process is :-

Two particles of equal mass have velocities 2hati ms^(-1) " and " 2hatj ms^(-1) . First particle has an acceleration (hati+hatj) ms^(-2) while the acceleration of the second particle is zero. The centre of mass of the two particles moves in ?

If velocity of an electron is (2 hati + 3hatj) ms^(-1) and it enters in the magnetic field of 4 hatkT , then

A particle has an initial velocity (3hati+2hatj) ms^(-1) and an acceleration of (0.2hati+0.3hatj)ms^(-2) . Its speed after 10s is

A particle has velocity (6t^3hati+8t^2hatj) ms^(-1) find the velocity of the particle