Molar conductance of `1M` solution of weak acid `HA` is `20 ohm^(-1) cm^(2) mol^(-1)`. Find `%` dissocation of `HA`:
`((^^_(m)^(o)(H^(+)) =350 S cm^(2) mol^(-1)),(^^_(m)^(o)(A^(-)) =50 S cm^(2) mol^(-1)))`

molar conductance of 1.5 M solution of an electrolyte is 138.9 S cm^(2) Mol^(-1) . Find the specific conductance.

Molar conductivity of a 0.01 M solution of a weak monobasic acids HA is 156cm^(2)mol^(-1) at 298 K. What is the pH of this solution if lamda_(m)^(@) of HA 390S cm^(2)mol^(-1)

Calculate degree of dissocation of 0.02 M acetic acid at 298K. Given that Lamda_(m) (CH_(3)COOH)= 17.37 S cm^(2) mol^(-1), lamda_(m)^(@) (H^(+)) = 345.8 S cm^(2) mol^(-1), lamda_(m)^(@) (CH_(3)COO^(-)) = 40.2S cm^(2) mol^(-1)

Calculate the degree of dissociation (alpha) of acetic acid if its molar conductivity (^^_(m)) is 39.05 S cm^(2) mol^(-1) Given lamda^(@) (H^(+)) = 349.6 cm^(2) mol^(-1) and lamda^(2) (CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)

Calculate the degree of dissociation (alpha) of acetic acid if its molar conductivity (^^_(m)) is 39.05 S cm^(2) mol^(-1) Given lamda^(@) (H^(+)) = 349.6 cm^(2) mol^(-1) and lamda^(2) (CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)

Molar conductivity of aqueous solution of HA is 200 S cm^(2) "mol"^(-1) , pH of this solution is 4. Calculate the value of pK_(a) (HA) at 25^(@) C Given: wedge_(M)^(infty) (NaA) = 100 S cm^(2) mol^(-1), wedge_(M)^(infty)(HCl)= 425 Scm^(2) "mol"^(-1) , wedge_(M)^(infty)(NaCl) = 125 Scm^(2)"mol"^(-1) .