12*ln(1)/(2)[sin^(-1)(2x)/(1+x^(2))+cos^(-1)(1-y^(2))/(1+y^(2))

tan{(1/2)sin^(-1)((2x)/(1+x^(2)))+1/2cos^(-1)((1-y^(2))/(1+y^(2)))} .

"tan"1/2["sin"^(-1)(2x)/(1+x^(2))+"cos"^(-1)(1-y^(2))/(1+y^(2))]

tan[1/2sin^(-1)((2x)/(1+x^(2)))-1/2cos^(-1)((1-y^(2))/(1+y^(2)))]=

tan[1/2Sin^(-1)((2x)/(1+x^(2)))-1/2Cos^(-1)((1-y^(2))/(1+y^(2)))]=

Find the value of: tan(1/2 [sin^(-1)((2x)/(1+x^2))+cos^(-1)((1-y^2)/(1+y^2))]),|x| 0 and x y < 1

Find the value of the following: tan [1/2[sin^(-1) ((2x)/(1+x^2))+cos^(-1) ((1-y^2)/(1+y^2))]], |x| 0 and x y < 1 .

Find the value of: tan1/2[sin^(-1)(2x)/(1+x^2)+cos^(-1)(1-y^2)/(1+y^2)],|x| 0 and x y" "<" "1

tan [(1) / (2) (sin ^ (- 1) ((2x) / (1 + x ^ (2))) + cos ^ (- 1) ((1-y ^ (2)) / ( 1 + y ^ (2)))]

sin^(-1)x+sin^(-1)y=cos^(-1)""{sqrt((1-x^(2))(1-y^(2)))-xy}

If "Cos"^(-1)x/a+"Cos"^(-1)y/b=(5pi)/12 and "Sin"^(-1)x/a-"Sin"^(-1)y/b=(pi)/12 then (x^(2))/(a^(2))+(y^(2))/(b^(2))=