" 1."quad " 4f "((x)/(3)+1,y-(2)/(3))=((5)/(3),(1)/(3))," tit "x" a?T "y" .The "

(1)/(2(3x+4y))=(1)/(5(2x-3y))=(1)/(4),

(3) 3x-2y=(5)/(2) (1)/(3)x+3y=-(4)/(3)

3x-2y=(5)/(2),(1)/(3)x+3y=(-4)/(3)

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

Solve the following simultaneous equations. (1)/(3x + y) + (1)/(3x - y) = (3)/(4) , (1)/(2(3x + y)) - (1)/(2(3x - y)) = - (1)/(8)

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

If y = 2x + 3x ^ (2) + 4x ^ (3) + ......., then (y) / (2) - (1.3) / (2!) ((Y) / (2) ) ^ (2) + (1.3.5) / (3!) ((Y) / (3)) ^ (3) -...... oo =

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

If y=f(x) is solution of differentiable equation (dy)/(dx)=y/x((1-3x^(2)y^(3)))/((2x^(2)y^(3)+1)) , then ( f(x).x)^(3) is equal to

If y=f(x) is solution of differentiable equation (dy)/(dx)=y/x((1-3x^(2)y^(3)))/((2x^(2)y^(3)+1)) , then ( f(x).x)^(3) is equal to