A seconds pendulum is shifted from a place where `g = 9.8 m//s^(2)` to another place where `g = 9.78 m//s^(2)`. To keep period of oscillation constant its length should be

A second pendulum is shifted from a plane where g = 9.8 m//s^(2) to another place where g = 9.82 m//s^(2) . To keep period of oscillation constant its length should be

Find the length of seconds pendulum at a place where g = 10 m/s^2 .

The length of seconds pendulum at a place wl}ere g = 4.9 m/ s^2 is

The length of seconds pendulum at a place wl}ere g = 4.9 m/ s^2 is

A second's pendulum is taken from a place where g=9.8 ms^(-2) to a place where g=9.7 ms^(-2) .How would its length be changed in order that its time period remains unaffected ?

A second's pendulum is oscillating at a place where g = 9.8 m//s^(2) . If the pendulum is shifted to a place where g = 9.6 m//s^(2) , then to keep this time period unchanged, how much change of length should be introduced ?

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g =4 pi^(2) m//s^(2) .