The binding energy of the electron in the ground state of `He` atom is equal to `E_(0)=24.6 eV`. Find the energy required to remove both the electrons from the atom.

The binding energy of an electron in the gorund state of He atom is equal to E_0 = 24.6 eV. Find the energy required to remove both electrons form the atom.

The binding energy of an electron in the gorund state of He atom is equal to E_0 = 24.6 eV. Find the energy required to remove both electrons form the atom.

The binding energy of an electron in the ground state of He is equal to 24.6 eV: Find the energy required to remove both electrons.

The biding energy of an electron in the ground state of He atom is 25 eV. Find the energy required to remove both the electrons.

The ionisation energy of an electron in the ground state of helium atom is 24.6eV. The energy required to remove both the electron is

The energy required in ionise a helium atom is equal to 24.6 eV The energy required to remove both the electron from the helium atom would be

" The binding energy for the third electron in the ground state of "Li" -atom (in eV) should be "

If the bineding energy of the electron of the electron in a hydrogen atom is 13.6 eV the energy required to remove the electron from the first excited state of Li ^(++) is