Home
Class 12
MATHS
Find the equation of tangent to the circ...

Find the equation of tangent to the circle `x^2 + y^2 - 8x - 10y - 8 = 0` which are parallel to `12y - 5x + 2 = 0`.

Text Solution

Verified by Experts

`x^2 + y^2 -8x - 10y - 8= 0`
`(x-4)^2 + (y-5)^2 - 25 - 16 - 8=0`
`(x-4)^2 + (y-5)^2 = 49= 7^2`
`12y- 5x + 2 = 0`
`12y - 5x+c = 0`
`(4,5) & r=7`
`d = |(12+5-5+4+c)/(sqrt(25+144))| = 7`
`|(60-20+c)/(sqrt(169))| = 7`
...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equations of the tangents to the circle x^(2) + y^(2) -8y - 8 = 0 which are parallel to the line 5 x -2 y = 2.

Find the equation of tangent to the circle x^(2) + y^(2) + 2x -3y -8 = 0 at (2,3)

Find the equation of the tangents to the circle x^(2)+y^(2)-4x+6y-12=0 which are parallel to x+y-8=0

Find the equations of the two tangents to the circle x^(2) +y^(2)- 8x - 10y - 8 = 0 which are perpendicular to the line 5x - 12y = 2.

Find the equation of tangents to x^(2)+ y^(2) -4x + 6y - 12=0 which are parallel to x + 2y -8=0 .

(i) Find the equation of the tangents to the circle x^(2)+y^(2)-4x+6y-12=0 which are parallel to x+y-8=0 (ii) Find the equations of the tangents to the circle x^(2)+y^(2)-5x+6y-12=0 which are paralel to x+2y-8=0

Find the equations of tangents to the circle x^2+y^2-22 x-4y+25=0 which are perpendicular to the line 5x+12 y+8=0

Find the equations of tangents to the circle x^2+y^2-22 x-4y+25=0 which are perpendicular to the line 5x+12 y+8=0

Find the equations of tangents to the circle x^2+y^2-22 x-4y+25=0 which are perpendicular to the line 5x+12 y+8=0