The current in a LR circuit builds up to `(3)/(4)th` of its steady state value in 4s . The time constant of this circuit is

The current in a LR circuit builds up to (3)/(40th of its steady state value ion 4s . The time constant. Of this circuit is

The current in an L-R circuit builds upto 3//4th of its steady state value in 4sec . Then the time constant of this circuit is

The current in an L-R circuit builds upto 3//4th of its steady state value in 4sec . Then the time constant of this circuit is

Time constant of LR circuit will be

Time constant of LR circuit will be

Current in an LR circuit attains one-fourth of its steady state value in 2 seconds. Calculate time constant for this circuit.

The current in an RL circuit builds up to one-third of its steady-state value in 5.00 s. Find the inductive time constant.

In an LR circuit, current at t = 0 is 20 A . After 2 s it reduces to 18 A . The time constant of the circuit is :