The energy of emitted photoelectrons from a metal is `0.9ev`, The work function of the metal is `2.2eV`. Then the energy of the incident photon is

A photon of wavelenth 3000 A strikes a metal surface, the work function of the metal being 2.20eV . Calculate (i) the energy of the photon in eV(ii) the kinetic energy of the emitted photo electron and (iii) the velocity of the photo electron.

A photon of wavelenth 3000 A strikes a metal surface, the work function of the metal being 2.20eV . Calculate (i) the energy of the photon in eV(ii) the kinetic energy of the emitted photo electron and (iii) the velocity of the photo electron.

The maximum kinetic energy of photoelectrons emitted from a metal surface increses from 0.4 eV to 1.2 eV when the frequency of the incident radiation is increased by 40% . What is the work function (in eV) of the metal surface?

The maximum kinetic energy of photoelectrons emitted from a metal surface increses from 0.4 eV to 1.2 eV when the frequency of the incident radiation is increased by 40% . What is the work function (in eV) of the metal surface?

A metal plate of area 1xx10^(-4)m^(2) is illuminated by a radiation 16 mW//m^(2) .The work function of the metal is 5eV.The energy of the incident photons is 10 eV and only 10% of it produces photo-electrons .The number of emitted photoelectrons per second and their maximum energy respectively will be

The energy of the incident photon is 20 eV and the work function of the photosensitive metal is 10 eV, the stopping potential is

A photon of wavelength 4x10^-7 m strikes a metal surface work function of the metal is 2.13eV calculate the kinetic energy of the emitted photoelectrons in eV

Two photons, each of energy 2.5eV are simultaneously incident on the metal surface. If the work function of the metal is 4.5eV then from the surface of the metal.

The work function of a metal is 4.2 eV . If radiation of 2000 Å fall on the metal then the kinetic energy of the fastest photoelectron is