`4Zn+10HNO_(3)rarr4Zn(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O`. In this reaction one mole of `HNO_(3)` is reduced by

4Zn+10HNO_(3)rarr 4Zn(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O In this reaction one mole of HNO_(3) is reduced by

4Zn +10HNO_(3) to 4Zn(NO_(3))_(2) +NH_(4)NO_(3)+3H_(2)O . In this reaction one mole of HNO_(3) is reduced by

4Mg+10HNO_(3)to4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O . In this reaction

4Mg+10HNO_(3)to4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O . In this reaction

For the reaction : Zn(s)+HNO_(3)(aq)toZn(NO_(3))_(2)(aq)+NH_(4)NO_(3)(aq)+H_(2)O(l) the change in oxidation number for per mole HNO_(2) is -

The ratio of coefficient of HNO_(3), Fe(NO_(3))_(2) and NH_(4)NO_(3) in the following redox reaction Fe + HNO_(3) rarr Fe (NO_(3))_(2) + NH_(4)NO_(3) + H_(2)O are respectively

The ratio of coefficient of HNO_(3), Fe(N)_(3))_(2) and NH_(4)NO_(3) in the following redox reaction Fe + HNO_(3) rarr Fe (NO_(3))_(2) + NH_(4)NO_(3) + H_(2)O are respectively

Cu + HNO_(3) rarr NO + Cu(NO_(3))_(2) + H_(2)O . Write the ionic equation and balance.