A conducting ring of radius `R` has charge `Q` distributed unevenly over it. If it rotates with an angular velocity `omega`, the equivalent current will be

A nonconducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity omega , the equivalent current will be

A non-conducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity omega the equivalent current will be:

A non-conducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity omega the equivalent current will be:

A non-conducting ring of radius r has charge q distributed unevenly over it. What will be the equivalent current if it rotates with an angular velocity Omega ?

As shown in figure there is a ring having radius R and charge q distributed uniformly over it. If ring is rotated with a constant angular velocity @, then torque acting on the ring due to magnetic force is (Assume that magnetic field B is parallel to plane of ring)

A thin disc of radius R and mass M has charge q uniformly distributed on it. It rotates with angular velocity omega . The ratio of magnetic moment and angular momentum for the disc is

A disc of mass m has a charge Q distributed on its surface. It is rotating about an XX' with a angular velocity omega . The force acting on the disc is