Home
Class 11
MATHS
The vertex of the parabola (y-2)^2=16(x-...

The vertex of the parabola `(y-2)^2=16(x-1)` is a.`(1,2)` b.`(-1,2)` c. `(1,-2)` d. `(2,1)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The vertex of the parabola (y-2)^(2)=16(x-1) is (1,2) b.(-1,2)c(1,-2)d.(2,1)

The vertex of the parabola x^(2)=8y-1 is :

The vertex of the parabola y^(2)=5 x+4 y+1 is

Vertex of parabola (y-3)^2=2(x+1) is ..........

The vertex of the parabola y^(2) - 4 y - x + 3 = 0 is a) (-1,3) b) (-1,2) c) (2,-1) d) (3,-1)

The focus of the parabola y=2x^2+x is a. (0,0) b. (1//2,1//4) c. (-1//2,0) d. (-1//4,1//8)

The vertex of the parabola y^(2) + 8x - 2y + 17 = 0 is (i) (1,-2) (ii) (-2,1) (iii) (1,2) (iv) (2,-1)

The coordinates of the vertex of the parabola (x + 1)^(2) =- 9(y +2) are