`6 (ax + by) = 3a + 2b` & `6(bx-ay) = 3b-2a`

Solve the following system of equations by method of cross-multiplication: 6(ax+by)=3a+2b,quad 6(bx-ay)=3b-2a

Solve: ax + by = a - b bx - ay = a + b

The line parallel to the x-axis and passing through the point of intersection of the lines ax + 2by + 3b = 0 and bx - 2ay - 3a = 0, where (a, b) ne (0, 0) is

The line parallel to the x-axis and passing through the intersection of the lines ax + 2by + 3b = 0 and bx – 2 ay – 3a = 0, where (a, b) != (0,0) is

Factoris the expression. 2ax ^(2) + 4 axy + 3bx ^(2) + 2 ay ^(2) + 6 bxy + 3 by ^(2)

Fractorise: (ax + by) ^(2) + (bx - ay)^(2)

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

Find the value of x and y: ax +by =a-b bx-ay =a+b