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Equivalent weight of MnO(4)^(ɵ) in acidi...

Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of:

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The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation Equivalent weight of MnO_(4)^(-) in acidic, basic and neutral media are in the ratio of

The equivalent weight of MnO_(4)^(-) ion in acidic medium is

Calculate equivalent weight of KMnO_4 in acidic medium.