An organic compound on analysis was found to contain 10.06 % Carbon,0.84 % Hydrogen and 89.10 % Chloride .What will be empirical formula of the substance ?

An organic compound on analysis was found to contain 16.27% carbon. 0.67% Hydrogen, 72.2% chlorine. The V.D. of the compound is equal to 73.75. Calculate the empirical formula and molecular formula of the compound.

An organic compound on analyis found to contain 92.3 % carbon and 7.7% hydrogen. It vapour density is 39. Find its molecular formula.

A hydrocarbon contains 80% carbon. What is the empirical formula of the compound?

A compound contains 34.8% Oxygen, 52.2% carbon and 13.0% Hydrogen. What is the empirical formula of the compound ?

A compound contains 34.8% Oxygen, 52.2% carbon and 13.0% Hydrogen. What is the empirical formula of the compound ?

A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

An organic compound is found to contain C=40.0%,H=6.66%.The empirical formula is

An organic compound contains 49.3 % carbon,6.84 % hydrogen and its vapour density is 73 Molecular formula of the compound is