To a `10mL` of `10^(-3) N H_(2)SO_(4)` solution water has been to make the total volume of one litre. Its `pOH` would be `:`

What will be the pOH of 0.5xx10^(-4)M H_(2)SO_(4) solution ?

10mL of N-HCl, 20mL of N//2 H_(2)SO_(4) and 30mL N//3 HNO_(3) are mixed togeher and volume made to one litre. The normally of H^(+) in the resulting solution is:

10mL of N-HCl, 20mL of N//2 H_(2)SO_(4) and 30mL N//3 HNO_(3) are mixed togeher and volume made to one litre. The normally of H^(+) in the resulting solution is:

10ml of N-HCl 20ml of N//2 H_(2)SO_(4) and 30 ml of N//3 HNO_(3) are mixed together and volume made to one litre. The normality of the resulting solution is -

22.7 mL of (N/10) Na_(2)CO_(3) solution neutralises 10.2 mL of a dilute H_(2)SO_(4) solution. The volume of water that must be added to 400 mL of this H_(2)SO_(4) solution in order to make it exactly N/10.

22.7 mL of (N/10) Na_(2)CO_(3) solution neutralises 10.2 mL of a dilute H_(2)SO_(4) solution. The volume of water that must be added to 400 mL of this H_(2)SO_(4) solution in order to make it exactly N/10.