What must be added to `11t^(3)+5t^(4)+6t^(5)-3t^(2)+t+5`, so that the resulting polynomial is exactly divisible by `4-2t+3t^(2)`?

If q(t)=4t^(3)+4t^(2)-t-1andq(-1/2)=0 , then determine the polynomial by which q(t) is divisible.

If u = 3t^(4) - 5t^(3) + 2t^(2) - 18t+4 , find (du)/(dt) at t = 1 .

(2-4t+5t^2)-(3t^2 + 2t -7) is equivalent to :

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the acceleration of particle at t=2 is

If 5t - 3 = 3t - 5 , then t =?

p(t)=t^(5)-3t^(4)-kt+7t^(2) In the polynomial function above, k is a nonzero constant. If p(t) is divisible by t-3, what is the value of k?

If t+1/t =5, then (2t)/(3t^(2)-5t+3) is equal to ……..

t^2 - 3, 2t^4 + 3t^3 - 2t^2 - 9t -12 check whether the first polynomial is a factor of second polynomial by dividing second polynomial by the first polynomial.

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is