Construct a triangle ABC in which BC = 7cm, `angleB=75^@` and AB + AC = 13 cm.

Explanation

Draw a base `BC` of length `7cm` Let's draw `/_B=75^@`. Let the ray be `BX`



Open the compass to length `AB+AC=13cm`. From point `B` as center cut an arc on ray `BX`. Let the arc intersect `BX` at `D`. Join `CD`.



Mark point `A` where perpendicular bisector intersects `BD`. Join `AC`.



`/_\ABC` is the required triangle.