Construct a triangle ABC in which BC = 8cm, `angleB=45^@` and AB - AC = 3.5 cm.

Explanation

Draw base `BC` of length `8cm`. Let's draw `/_B=45^@`. let the ray be `BX`.



Open the compass to length `AB-AC=3.5cm`. From point `B` as center cut an arc on ray `BX`. Let the arc intersect `BX` at `D`. Join `CD`

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Draw perpendicular bisector of `CD`. Mark point `A` where perpendicular bisector intersects `BD`. Join `AC`.



`/_\ABC` is the requires triangle.